If `(1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1)` then `C+D`

If sec theta+tan theta=x, then tan theta=(x^(2)+1)/(x) (b) (x^(2)-1)/(x)( c) (x^(2)+1)/(2x) (d) (x^(2)-1)/(2x)

(2x^(3)+x^(2)-5)/(x^(4)-25)=(Ax+B)/(x^(2)-5)+(Cx+D)/(x^(2)+5) rArr(A,B,C,D)

If (x^(3))/((x-1)(x-2))=Ax+B+(C )/(x-1)+(D)/(x-2) , then A,B,C and D , respectively are ____________.

If sec theta+tan theta=x, then sec theta=(a)(x^(2)+1)/(x) (b) (x^(2)+1)/(2x)(c)(x^(2)-1)/(2x) (d) (x^(2)-1)/(x)

Find the constants a,b,c and d , respectively, if (1)/(x^(4)-x)=(a)/(x)+(b)/(x-1)+(cx+d)/(x^(2)+x+1) .

(d)/(dx)[log{e^(x)((x-2)/(x+2))^(3/4)}] equals (x^(2)-1)/(x^(2)-4) (b) 1 (c) (x^(2)+1)/(x^(2)-4) (d) e^(x)(x^(2)-1)/(x^(2)-4)

int(x^(4)+x^(2)+1)/(x^(2)+x+1)dx=Ax^(3)+Bx^(2)+Cx+D then A+B+C+D is equal to