A `0.01M` solution of `K_(3) [Fe(CN)_(6)]` is `50%` dissociated at `27^(@)C` then the osmotic pressure of solution will be

A 0.1M solution of potassiu ferrocyanide is 46% dissociated at 18^(@)C . What will be its osmotic pressure?

A decimolar solution of pottassium ferrocyanide is 50% dissociated at 300 K. The osmotic pressure of the solution is (Given R=8.314JK^-1mol^-1 )

A decimolar solution of potassium ferrocyanide is 50% dissociated at 300K . Calculate osmotic pressure of the solution. (Given S = 8.341 JK^(-1) mol^(-1) )

The osmotic pressure of one molar solution at 27^(@)C is