`int_0^(pi/2)(dx)/(1+2cosx)`

int_(0)^(pi//2)(dx)/(2+cosx)=

int_(0)^(pi//2)(dx)/(2+cosx)=

Evaluate the following: int_0^(pi/2)dx/(1+cosx)

Find the Definite Integrals : int_0^(pi/2) dx /(2 + cosx)

Evaluate: int_0^(pi//2)(cosx)/(1+cosx+sinx)dx

Evaluate: int_0^(pi//2)(cosx)/(1+cosx+sinx)dx

The value of I=int_(0)^(pi//2) (1)/(1+cosx)dx is

The value of I=int_(0)^(pi//2) (1)/(1+cosx)dx is

Given int_0^(pi/2)(dx)/(1+sinx+cosx)=log2. Then the value of integral int_0^(pi/2)(sinx)/(1+sinx+cosx)dx is equal to (a) 1/2log2 (b) i spi/2-log2 pi/4-1/2log2 (d) pi/2+log2

Evaluate int_0^(pi/2)(cosx)/(1+sinx)^2dx