`((x+2)/3)-((x+1)/5)=((x-3)/4)-1`

(x+2)/(3)-(x+1)/(5)=(x-4)/(3)-1

((x-1)/(x-2))-((x-2)/(x-3))=((x-3)/(x-4))-((x-4)/(x-5))

Simplify :((-3)/(2)x(4)/(5))+((9)/(5)x(-10)/(3))-((1)/(2)x(3)/(4))

(5x)/(3)-(x-2)/(3)=(9)/(4)-(1)/(2)(x-(2x-1)/(3))

Solve: (x-2)/(x-3)+(x-4)/(x-5)=3(1)/(3),xne3,5.

3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11;x!=(3)/(5),-(1)/(7)

Solve x:(3x-1)/(5)=(1+x)/(2)=3-(x-1)/(4)

((x+1)-(2x+4))/(3-5x)=(1)/(23)

Check whether the following are quadratic equations : (1) (x-1)^(2)=2(x-3) (2) x^(2)-2x=(-2)(3-x) (3) (x-2)(x+1)=(x-1)(x+3) (4) (x-3)(2x+1)=x(x+5) (5) (2x-1)(x-3)=(x+5)(x-1) (6) x^(2)+3x+1=(x-2)^(2) (7) (x+2)^(3)=2x(x^(2)-1) (8) x^(3)-4x^(2)-x+1=(x-2)^(3)