A point `(x, y)` in the first quadrant lies on a line with intercepts (a,0) and (0, b), where `a, b > 0`.Rectangle `Delta _1` has vertices `(0, 0), (x, 0), (x, y) and (0, y)` while rectangle `Delta _2` has vertices `(x, y),(x, b). (a, b) and (a, y).` The ratio of the area of `Delta_1` to that of `Delta _2` is

A point (x,y) in the first quadrant lies on a line with intercepts (a,0) and (0,b) where a,b>0 .Rectangle M has vertices (0,0) , (x,0) , (x,y) and (0,y) while rectangle N has vertices (x,y) , (x,b) , (a,b) and (a,y) .The ratio of the area of M to that of N is 1) 1 2) 2 3) (1)/(2) 4) dependent on the value of a,b,x and y

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))" and B(x_(2),y_(2)) is

A triangle is formed by vertices (0, 0), (x, y), (-x, y) on xy-plane. If the point (x, y) and (-x, y) lies on y =-x^2 54 , then maximum area of triangle is

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))B(x_(2),y_(2)) is

" The area of the triangle OAB with vertices "O(0,0),A(x_(1),y_(1))" and "B(x_(2),y_(2))" is "ul(sq)" units "

Let ABC is a triangle whose vertices are A(1, –1), B(0, 2), C(x', y') and area of triangleABC is 5 and C(x', y') lie on 3x + y – 4lambda = 0 , then

Let ABC is a triangle whose vertices are A(1, –1), B(0, 2), C(x', y') and area of triangleABC is 5 and C(x', y') lie on 3x + y – 4lambda = 0 , then

Find the area of the triangle formed theby lines y-x=0,x+y=0 and x-k=0 .

Find the area of the triangle formed by the lines y-x=0,x+y=0 and x-k=0 .

Find the area of the triangle formed by the lines y-x=0,x+y=0 and x-k=0