If `y=f(x)` is symmetric about the lines `3x +4y+1=0 and 4x-3y-7=0` then it must be symmetric about

Assertion (A) : The function f(x) = cos x is symmetric about the line x = 0 Reason (R): Every even function is symmetric about y-axis

Statement 1: The function f (x) = sin x is symmetric about the line x = 0. Statement 2: Every even function is symmetric about y-axis.

Statement 1: The function f (x) = sin x is symmetric about the line x = 0. Statement 2: Every even function is symmetric about y-axis.

If f(x) is a real-valued function defined as f(x) = In (1 - sin x), then the graph of f(x) is a)symmetric about the line x = pi b)symmetric about the y-axis c)symmetric about the line x=pi/2 d) symmetric about the origin

The symmetrical from of the lines x+y+z-1=0 and 4x+y-2z+2=0 are -

Statement -1: f(x) is invertible function and f(f(x)) = x AA x in domain of f(x), then f(x) is symmetrical about the line y = x. Statement -2: f(x) and f^(-1)(x) are symmetrical about the line y = x.

If f(x) is a real-valued function defined as f(x)=In (1-sinx), then the graph of f(x) is (A) symmetric about the line x =pi (B) symmetric about the y-axis (C) symmetric and the line x=(pi)/(2) (D) symmetric about the origin

If f(x) is a real-valued function defined as f(x)=In (1-sinx), then the graph of f(x) is (A) symmetric about the line x =pi (B) symmetric about the y-axis (C) symmetric and the line x=(pi)/(2) (D) symmetric about the origin

If f(x) is a real-valued function defined as f(x)=In (1-sinx), then the graph of f(x) is (A) symmetric about the line x =pi (B) symmetric about the y-axis (C) symmetric and the line x=(pi)/(2) (D) symmetric about the origin

The equation of the line x+y+z-1=0 and 4x+y-2z+2=0 written in the symmetrical form is