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Prove that : cos^2alpha+cos^2(alpha+beta...

Prove that : `cos^2alpha+cos^2(alpha+beta)-2cosalphacosbetacos(alpha+beta)=sin^2beta`

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Given,
`cos^2alpha+cos^2(alpha+beta)−2cosalphacosbetacos(alpha+beta)`
`⇒cos^2alpha+cos(alpha+beta)[cos(alpha+beta)−2cosalphacosbeta]`
`=>cos^2alpha+cos(alpha+beta)[cosalphacosbeta−sinalphasinbeta−2cosalphacosbeta]`
`⇒cos^2alpha+cos(alpha+beta)[cosalphacosbeta−sinalphasinbeta−2cosalphacosbeta]`
`⇒cos^2alpha−cos(alpha+beta) [sinalphasinbeta+cosalphacosbeta]`
`⇒cos^2alpha−cos(alpha+beta)cos(alpha−beta)`
...
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