An arc is in the form of a semi-ellipse. It is `8m` wide and `2m` high at the centre. Find the height of the arch at a point `1. 5 m` from one end.

Explanation

Here,
`2a=8`

`a=4,b=2`


Therefore, the equation of the semi-ellipse is `(x^2)/16​+(y^2)/4​=1,y≥0 ...(1)`

Let B be a point on the major axis such that AB=1.5 m

On substituting the value of x with −2.5 in equation (1), we obtain

`=>((−2.5)^2)/(16)​+(y^2)/4​=1`

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