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Five boys and five girls form a line wit...

Five boys and five girls form a line with the boys and girls alternating. Find the number of ways of making the line when all girls are together.

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To solve the problem of arranging 5 boys and 5 girls in a line such that all girls are together and the arrangement alternates between boys and girls, we can follow these steps: ### Step 1: Treat the group of girls as a single unit Since all girls must be together, we can treat them as one single unit or block. This means we now have 6 units to arrange: 5 boys + 1 block of girls. **Hint:** When a group of items must stay together, consider them as a single unit. ### Step 2: Arrange the boys and the block of girls ...
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RD SHARMA-PERMUTATIONS-Solved Examples And Exercises
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  2. Five boys and five girls form a line with the boys and girls alterna...

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  13. Prove that (n !)^2 < n^n n! < (2n)!, for all positive integers n.

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  14. Prove that (n !+1) is not divisible by any natural number between 2 a...

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  15. Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

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  16. If (n !)/(2!(n-2)!) and (n !)/(4!(n-4)!) are in the ratio 2:1 , find t...

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  17. Find n , if (n+2)! =2550xxn ! (ii) (n+1)! =12xx(n-1)!

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  18. If 1/(9!)+1/(10 !)=x/(11 !) , find xdot

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  19. If ((2n)!)/(3!(2n-3)!)a n d(n !)/(2!(n-2)!) are in the ratio 44 :3, fi...

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