Home
Class 11
MATHS
The number of different of different way...

The number of different of different ways in which 8 persons can stand in a row so that between two particular persons A and B there are always two persons, is

Text Solution

Verified by Experts

We will first choose the 2 people that are between A and B in `6_(C_2)`​ ways
A,B and the two people between them can be arranged in 2 ways each.
The total number of arrangements of this one unit is `2×2=4`
So the total number of arrangements possible is `6_(C_2)​×5!×4=60×5!`
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    RD SHARMA|Exercise Solved Examples And Exercises|81 Videos
  • PROBABILITY

    RD SHARMA|Exercise Solved Examples And Exercises|280 Videos

Similar Questions

Explore conceptually related problems

The number of different ways in which 8 persons can stand in a row so that between two particular person A and B there are always two person, is

In how many ways five persons can stand in a row ?

The number of ways in which seven persons can be arranged at a round table if two particular persons may not sit together, is

The number of ways of arranging 9persons around a circle if there are two other persons between two particular persons is:

Suppose n ( ge 3) persons are arranged in a row. The probability that two particular persons are not together is

You are given 8 balls of different colour (black,white ......). The number of ways in which these balls can be arranged in a row so that the two balls of particular colour (say red and white) may never come together is-

20 persons are invited for a party.The different number of ways in which they can be seated on acircular table with two particular persons seated,on either side of the host is

RD SHARMA-PERMUTATIONS-Solved Examples And Exercises
  1. In how many ways can the letters of the word PERMUTATIONS be arrang...

    Text Solution

    |

  2. Number of ways in which a lawn-tennis mixed double be made from sev...

    Text Solution

    |

  3. The number of different of different ways in which 8 persons can stand...

    Text Solution

    |

  4. Prove that 33! is divisible by " 2^15. what is the largest integer n s...

    Text Solution

    |

  5. Prove that (n !)^2 < n^n n! < (2n)!, for all positive integers n.

    Text Solution

    |

  6. Prove that (n !+1) is not divisible by any natural number between 2 a...

    Text Solution

    |

  7. Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

    Text Solution

    |

  8. If (n !)/(2!(n-2)!) and (n !)/(4!(n-4)!) are in the ratio 2:1 , find t...

    Text Solution

    |

  9. Find n , if (n+2)! =2550xxn ! (ii) (n+1)! =12xx(n-1)!

    Text Solution

    |

  10. If 1/(9!)+1/(10 !)=x/(11 !) , find xdot

    Text Solution

    |

  11. If ((2n)!)/(3!(2n-3)!)a n d(n !)/(2!(n-2)!) are in the ratio 44 :3, fi...

    Text Solution

    |

  12. How many permutations of the letters of the word MADHUBANI do not b...

    Text Solution

    |

  13. Find the probability that in a random arrangement of the letters of th...

    Text Solution

    |

  14. How many numbers can be formed with the digits 1, 2, 3, 4, 3, 2, 1 so ...

    Text Solution

    |

  15. If the letters of the word ‘MOTHER’ are written in all possible orders...

    Text Solution

    |

  16. In how many ways can the letters of the word PERMUTATIONS be arrang...

    Text Solution

    |

  17. In how many ways can the letters of the word PERMUTATIONS be arrange...

    Text Solution

    |

  18. (i) How many different words can be formed with letters of the word ‘S...

    Text Solution

    |

  19. How many words can be formed using the letter A thrice, the letter B ...

    Text Solution

    |

  20. How many 4 letters words can be formed using the letters of the words ...

    Text Solution

    |