The system shown in figure is in equilibrium. Find the magnitude of tension in each string, `T_(1), T_(2), T_(3)` and `T_(4) ( g = 10 m//s^(-2))`

Explanation

F.B.D. of block 10kg F.B.D. of point 'A''

`sumF_(y)= 0`
`T_(2) cos 30^(@) =T_(0) =100N`
`T_(2)=(200)/(sqrt(3))`
`sum F_(x) =0`
`T_(1) = T_(2) sin 30^(@) = ( 200)/( sqrt(3)). (1)/(2) = ( 100)/( sqrt(3)) N`
F.B.D. of point of 'B'
`sum F_(y) = 0 `
`rArr T_(4) cos 60^(@) = T_(2) cos 30^(@)`

and `sum F_(x) = 0`
`rArr T_(3) + T_(2) sin 30^(@) = T_(4) sin 60^(@)`
`:. T_(3) ( 200)/( sqrt( 3)) N, T_(4) = 200N `