A 5kg block has a rope of mass 2 kg attached to its underside and a 3 kg block is suspended from the other end of the rope. The whole system is accelerated upward is `2 m//s ^(2)` by an external force `F_(0) `.
What is the force on rope ?

Explanation

For calculating the value of `F_(0)`, consider two blocks with the rope as a system.
F.B.D. of whole system
According to Newton's second law, net foce on rope.
F = ma = ( 2) (2) = 4N