A 5kg block has a rope of mass 2 kg attached to its underside and a 3 kg block is suspended from the other end of the rope. The whole system is accelerated upward is `2 m//s ^(2)` by an external force `F_(0) `.
What is the tension at middle point of the rope ? `( g= 10 m//s^(2))`

Explanation

For calculating the value of `F_(0)`, consider two blocks with the rope as a system.
F.B.D. of whole system
For calculating tension at the middle point we draw F.B.D. of 3kg block with half of the rope ( mass 1 kg ) as shown.
`T - 4g = 4. ( 2) = 48N`