Home
Class 12
PHYSICS
Find out the contact force between the 2...

Find out the contact force between the 2kg & 4 kg block as shown in figure.

Text Solution

Verified by Experts

On an incline plane acceleration of the block is independent of mass. So both the blocks will move with the same acceleration ( g sin `37^(@)` ) so the contact force between them is zero.
Promotional Banner

Topper's Solved these Questions

  • NLM & FRICTION

    MOTION|Exercise SOLVED EXAMPLE|16 Videos
  • NLM & FRICTION

    MOTION|Exercise EXERCIS-1|80 Videos
  • NLM & FRICTION

    MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 3 Section-B|12 Videos
  • ONE DIMENSION MOTION

    MOTION|Exercise Exercise - 3 |Section - B Previous Year Problems | JEE MAIN|12 Videos

Similar Questions

Explore conceptually related problems

Find the contact force between the 3kg and 3kg block as shown in figure.

Find out the contact force between 2kg & 3kg block placed on the incline plane as shown in figure.

Find the contact force on the 1 kg block.

Find the nomral force between 2 kg and 3 kg blocks.

Three blocks of masses 2kg,3kg and 5kg are placed in contact as shown in the diagram. A horizontal force of 30N is applied on 2kg block. Find the contact force between (a) 2kg and 3kg block and (b) 3kg and 5kg block.

Three blocks of masses 4 kg, 2 kg and 1 kg respectively are in contact on a frictionless table as shown in the figure. If a force of 14N is applied on the 4 kg block, the contact force between the 4 kg and the 2 kg block will be

Find the contact force between the block and acceleration of the blocks as shown in figure.

Find the force exerted by 5kg block on floor of lift, as shown in figure. ( Take , g=10 ms^(-2) )

Find the force of interaction between the bodies as shown in fig. Blocks are in contact.

Find the force of friction acting between both the blocks shown in the figure. u = .4 5 Kg F= 20 N 10 Kg

MOTION-NLM & FRICTION-EXAMPLE
  1. A 5kg block has a rope of mass 2 kg attached to its underside and a 3 ...

    Text Solution

    |

  2. A 5kg block has a rope of mass 2 kg attached to its underside and a 3 ...

    Text Solution

    |

  3. Find out the contact force between the 2kg & 4 kg block as shown in fi...

    Text Solution

    |

  4. Find out the contact force between 2kg & 3kg block placed on the incli...

    Text Solution

    |

  5. One end of string which passes through pulley and connected to 10kg m...

    Text Solution

    |

  6. In the figure shown, find out acceleration of each block.

    Text Solution

    |

  7. Find the acceleration of each block in the figure shown below, in term...

    Text Solution

    |

  8. Two blocks A and B each having a mass of 20kg, rest on frictionless su...

    Text Solution

    |

  9. Two block m(1) and m(2) are placed on a smooth inclined plane as show...

    Text Solution

    |

  10. A block of mass 'm' is kept on the ground as shown in figure. (i) Dr...

    Text Solution

    |

  11. If the breaking strength of string is 600N then find out the maximum a...

    Text Solution

    |

  12. A 60kg painter on a 15 kg platform. A rope attached to the platform an...

    Text Solution

    |

  13. A 60kg painter on a 15 kg platform. A rope attached to the platform an...

    Text Solution

    |

  14. A 60kg painter on a 15 kg platform. A rope attached to the platform an...

    Text Solution

    |

  15. Two blocks are connected by a spring of natural length 2m.The force co...

    Text Solution

    |

  16. Two blocks are connected by a spring of natural length 2m.The force co...

    Text Solution

    |

  17. Force constant of a spring is 100 N//m. If a 10kg block attached with ...

    Text Solution

    |

  18. Find out the acceleration of 2kg block in the figures shown at the ins...

    Text Solution

    |

  19. Two blocks A and B of same mass m attached with a light spring are su...

    Text Solution

    |

  20. Find out the acceleration of 1kg, 2kg and 3kg block and tension in the...

    Text Solution

    |