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One end of string which passes through pulley and connected to 10kg mass at other end is pulled by 100N force. Find out the acceleration of 10kg mass. `( g = 9.8 m//s^(2))`

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Since string is pulled by 100N force. So tension in the string is 100N.
F.B.D. of 10kg block
`100 - 10g = 10a `

`100 - 10 xx 9.8 - 10 a `
`a = 0.2 m//s^(2)`
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