Mass `m_(1) ` & `m_(2)` are placed on a rough inclined plane as shown in figure.Find out the acceleration of the blocks and contact force in between these surface.

Explanation

As we known if `mu_(1) gt mu_(2)` both will travel together so `a_(1) = a_(2)=a `
F.B.D.

which is equivalent to
`a = ( 3 g sin 37^(@) - ( f _(1) +f_(2)))/( 3)`
`a = ( 18-7.2)/( 2) =3.6 m//sec^(2)`

Now F.B.D. of 1 kg block is
` g sin 37^(@) + N -4 = (1)a `
`N = 3.6 + 4-6 = 1.6 `Newton