Home
Class 12
PHYSICS
Figure shows two blocks tied by a string...

Figure shows two blocks tied by a string. A variable force `F =5t` is applied on the block. The coefficient of friction for the blocks are 0.6 and 0.5 respectively. Find the frictional force between blocks and ground as well as tension in the string at t = 1s

Text Solution

Verified by Experts


At `t = 1s`,`F = 5 xx 1 =5N`
Maximum value of friction force
`f_(A) = mu N =0.5 xx 20 = 10N`
To keep the block stationary the magnitude of frictional force should be 5N. So
`f_(A) = 5N`
Now from the figure it becomes clear that if
`f_(A)5N` & F = 5N ,Tension T = 0
Since tension is not in application so frictional force on block B is 0 i.e.,
`f_(B ) = 0`
Promotional Banner

Topper's Solved these Questions

  • NLM & FRICTION

    MOTION|Exercise EXERCIS-1|80 Videos

  • NLM & FRICTION

    MOTION|Exercise EXERCISE-2|66 Videos

  • NLM & FRICTION

    MOTION|Exercise EXAMPLE|47 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 3 Section-B|12 Videos

  • ONE DIMENSION MOTION

    MOTION|Exercise Exercise - 3 |Section - B Previous Year Problems | JEE MAIN|12 Videos

Similar Questions

Explore conceptually related problems

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, then the magnitude of the frictional force acting on the block is

A block of mass 0.1 is held against a wall applying a horizontal force of 5N on block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is:

Two blocks of masses 2 kg and 4kg are connected through a massless inextensible string. The co-efficient of fricition between 2kg block and ground is 0.4 and the coefficient of friction between 4kg block and ground is 0.6. The forces F_(1)=10N and F_(2)=20N are applied on the blocks as shown in the figure. Calculate the frictional force between 4 kg block and ground (Assume initially the tension in the string was just before forces F_(1) and F_(2) wer applied).

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 1kg is pressed against a wall by applying a horizontal force of 10N on the block. If the coefficient of friction between the block and the wall is 0.5 ,magnitude of the frictional force acting on the block is

A block of mass m is stationary on a horizontal surface. It is connected with a string which has no tension. The coefficient of friction between the block and surface is m . Then , the frictional force between the block and surface is:

A block of mass 2 kg is placed on the floor (mu=0.4) . A horizontal force of 7 N is applied on the block. The force of friction between the block & floor is f_(s) . Find the f_(s) .