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FIND MAXIMUM ACCELERATION OF BLOCK A....

FIND MAXIMUM ACCELERATION OF BLOCK A.

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The lower block A will move ony due to friction force
F.B.D.
`f_("max") =mu N =( 0.5) ( 20) = 10 N`
F.B.D. of 4 kg blocks

The maximum acceleration of 4 kg block is
`rArr a_("max") = ( 10)/( 4) = 2.5 m//s^(2)`
This is the maximum acceleration for which both the blocks move together.

`F_("max")` for which both the bloks will move together
`F_("max") = 2.5 xx 6 = 15N`
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