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The rear side of a truck is open and a b...

The rear side of a truck is open and a box of 40 kg mass is placed 5 m from the openend as shown The coefficient of friction between the box and the surface below it is 0.15 On a straight road the truck starts from rest and accelerates with `2 ms^(-2)` At what distance from the starting point does the box fall off the truck ? (Ignore the size of the box )
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Text Solution

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In the reference frame of the truck FBD of 40kg block

Net force `rArr ma -mu N rArr 40 xx2 - (15)/( 100) xx 40 xx 10 `
`ma_("block") rArr 80-60 rArr a_("block") = ( 20)/( 40) =(1)/(2) m//s^(2)`
This acceleration of the block in reference frame of truck so time taken by box to fall down from truck
`S_("rel") = u_("rel")t + ( 1)/( 2) a_("rel") t^(2) rArr 5= 0 + (1)/(2) xx (1)/(2) xxt^(2) rArrt^(2) = 20`
So distance moved by the truck
`rArr (1)/(2) xx a_("truck") xx t^(2)`
`rArr (1)/(2) xx 2 xx(20) = 20 ` meter
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