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A particle slides down a smooth inclined...

A particle slides down a smooth inclined plane of elevation `theta` fixed in a elevator going up with an acceleration `a_(0)`. The base of the inline has a length L.

A

The acceleration of the particle with respect to the incline plane is `( g+ a_(0)) cos theta `

B

The time taken by the particle to reach the bottom `((2L)/((g+a_(0))sin theta))^(1//2)`

C

The acceleration of particle with respect too the incline plane `( g + a_(0)) sin theta `

D

The time taken by the particle to reach the bottom `((2L)/((g+a_(0))sin theta cos theta))^(1//2)`

Text Solution

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The correct Answer is:
C, D
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Knowledge Check

  • A particle slides down a smooth inclined plane of elevation , fixed in an elevator going up with an acceleration a0 (figure). The base of the incline has a length L. Find the time taken by the particle to reach to the bottom -

    A
    `[(2L)/(g sin theta cos theta )]^(1//2)`
    B
    `[(2L)/((g-a_(0))sin thetacos theta )]^(1//2)`
    C
    `[(2L)/((g+a_(0))cos theta )]^(1//2)`
    D
    `[(2L)/((g+a_(0))sinthetacos theta )]^(1//2)`

  • A particle slides down a smooth inclined plane of elevation fixed in an elevator going with an acceleration a as shown in the figure. The base of the incline has a length L. If the elevator going up with constant velocity, the time taken by the particle to reach the bottom is

    A
    `((2L)/((gsin theta cos theta)))^(1//2)`
    B
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    D
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    B
    `(9)/(8)sqrt3s`
    C
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