A block of base `10 cm xx 10 cm` and height `15 cm` is kept on an inclined plane. The corfficient of friction between them is `sqrt(3)`. The inclination `theta` of this inclined plane from the horizontal plane is gradually increased frm `0^@`. Then

Options

A. at `theta = 30^(@)` , the block will start sliding down the plane
B. the block will remain at rest on the plane up to certain `theta` and then it will topple
C. at `theta =60^(@)`, the block will start sliding down the plane and continue to do so at higher angles
D. at `theta = 60^(@)`, the block will start sliding down the plane and on further increasing `theta`, it will topple at certain `theta`

Answer

B