A uniform wooden stick of mass 1.6 kg and length l rests in an inclined mannar on a smooth, vertical wall of height `h(ltl)` such that a small portion of the stick extends beyond the wall. The reaction force of th wall on the stick is perpendicular to the stick. The stick makes an angle of `30^@` with the wall and the bottom of the stick is on a rough floor. The reaction of the wall on the stick is equal in magnitude to the reaction of the floor on the stick. The ratio h/l and the friectional force f at the bottom of the stick are `(g = 10 ms^2)`

Options

A. `( h )/( l ) =( sqrt( 3))/( 16), f =( 16sqrt(3))/( 3) N`
B. `( h )/( l ) =( 3)/( 16), f =( 16sqrt(3))/( 3) N`
C. `( h )/( l ) =(3sqrt( 3))/( 16), f =( 8sqrt(3))/( 3) N`
D. `( h )/( l ) =(3sqrt( 3))/( 16), f =( 16sqrt(3))/( 3) N`

Answer

D