Two sources `S_1 " and "S_2` separated 2.0 m, vibrate according to equation `y_1= 0.03 sin pi t " and " y_2= 0.02 sin pi t " where "y_1, y_2` and t are in M.K.S unit. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle co-linear with `S_1 " and "S_2` and located at a point
To the right of `S_2`.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Identify the given parameters
- The equations for the waves are:
- \( y_1 = 0.03 \sin(\pi t) \) (Amplitude \( A_1 = 0.03 \, \text{m} \))
- \( y_2 = 0.02 \sin(\pi t) \) (Amplitude \( A_2 = 0.02 \, \text{m} \))
- The distance between the sources \( S_1 \) and \( S_2 \) is \( d = 2.0 \, \text{m} \).
- The velocity of the waves \( v = 1.5 \, \text{m/s} \).
...