If charge q1 is fixed and q2 is free to move then find out the velocity of q2 when it reaches distance r2 after it is release from a distance of `r_(1)` from `q_(1)` as shown in figure Assume friction is absent).

Find v of `q_(2)` when it reaches stance r2 after it is released from rest.

Explanation

`a = (kq_(1)q_(2))/(mx^(2))`
`int_(0)^(v)"vdv"=(kq_(1)q_(2))/(m)int_(r_(1))^(r_(2))(dx)/(x^(2))`
`implies(v^(2))/(2)=(kq_(1)q_(2))/(m)[1/r_(1)-1/r_(2)]`
`impliesv=(2kq_(1)q_(2))/m[1/r_1-1/r_2]`