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Two particles, each having a mass of 5 g...

Two particles, each having a mass of 5 gm and charge `1.0 × 10^(-7)C`, stay in limiting equilirbium on a horizontal table with a separation of 10 cm between them. The coefficient of friction between each particle and the table is the same. Find the value of this coefficient.

Text Solution

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Consider particle A. Forces acting on A are coulombic force and frictional force under limiting condition friction will be limiting and will be equal to coulombic force.
`F_C=(Kq^2)/(r^2)=(9xx10^9xx(10^-7))/((10xx10^(-2))^2)=9xx10^-3N`
`f=muN=mumg=mu(5xx10^-3xx10)=mu(5xx10^-2N)`
For equilibrium,
We have `F_c=f`
`0=9xx10^(-3)-mu(5xx10^(-2))`
`impliesmu=(9xx10^(-3))/(5xx10^(-2))=0.18`
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