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Given an equilateral triangle with side ...

Given an equilateral triangle with side l. Find E at the centroid. The linear charge density is as shown in figure.

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The electric field strength due to the three rods AB, BC and CA are as shown in figure
`vec(E)_(AC)=(-2Klamda)/(l//sqrt(3))(2 sin 30^@)(costhetahati-sinthetahatj)`
`vec(E)_(AB)=(2Klamda)/(l//sqrt(3))(2 sin 30^@)(costhetahati-sinthetahatj)`
`vec(E)_(BC)=(2Klamda)/(l//sqrt(3))(2 sin 30^@)hatj`

`vecE_("net")=vecE_(AC)+vecE_(AB)+vecE_(BC)`
`vecE_("net")=(-lamda)/(2piin_0l)hatj`
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