In the given arrangement find the electric field at C in the figure. Here the U-shaped wire is uniformly charged with linear charge density `lambda`. [0]

Explanation

The electric field due to the three parts of U-shaped wire are shown in figure (b). Thus we have
`vecE_("net")=(E_(x_(1))+E_(x_(2)))hati+(E_(y_(1))+E_(y_(2))+E_(y_(3)))hati`
`vecE_("net")=((Elamda)/(a)-(Klamda)/(a))hati+((2Elamda)/(a)-(Elamda)/(a)-(Klamda)/(a))hatj=0`
Thus E.F. due to given arrangement at C = 0