Find out the angular frequency of the dipole when it crosses the mean position.

Explanation

`0-PE cos 37^@=1/2Iomega^(2)`
`1/2 Iomega^(2)=(PE)/(5)`
`(2ml^(2))/(2)omega^(2)=(2ql.E)/(5) implies omega=sqrt((2qE)/(5ml))`