In Gauss' s theorem `underset(s)oint"Eds"=(q)/(epsilon_(0))` The surface integral is evaluated by choosing a closed surface called the Gaussian surface. Here

Options

A. The closed surface can be of any shape or size.
B. q is the net charge enclosed inside the Gaussian surface, charges outside the surface are not considered.
C. E is the electric field due to all the charges both inside and outside the surface.
D. The exact location of the charges inside the surface does not affect the value of the integral.

Answer

A, B, C, D