Find charge on each capacitor

Explanation

Charge on ` C_1 =(x- 10 )C_1 `
Charge on ` C_2 =(x-0) C_2`
. Charge on ` C_2 =(x-20 ) C_2 `
Now from charge conservation at node x

` (x-10 ) C_1+ (x- 0)C_2+ (x-20 ) C_3=0`
`rArr " " 2x-20 + 2x+4x -80 =0rArr x= 25//2`
` so Q_(c_1) =((25)/( 2) -10 ) 2mu C =5mu C `
` Q_(C_1) =( 25)/(2)xx 2mu C = 25mu C `
`Q_(c_1) =( 25//2- 40) xx 4mu C =-30mu C `