When switch is shifted from 1 to 2 then find charge flown in circuit and heat generated.

Explanation

Initially
` (##MOT_CON_JEE_PHY_C25_SLV_032_S01.png" width="80%">
`(q)/(c ) 1 -5 + 10 =0 `
` rArr " "q_1 =10 mu F `
Finally
` rArr " " q_1 =10 xx 2 mu C =20 mu C `
So charge Flown (Q) ` = (q_2 -q_1 ) =10 mu C `
Work done by bettery ` =QV = 10 xx10 = 100 mu J`
` (##MOT_CON_JEE_PHY_C25_SLV_032_S02.png" width="80%">
So
Heat
= ` [W.D_B-` { final initial }energy of capacitor ]
` =[100- {(1)/( 2) xx 2 xx ( 0 ) ^(2) -(1)/(2) xx 2xx 5 }]muJ `
` = [100 -{100 -25}]mu J = 25 mu J`