Find out current in the circuit and charge on capacitor which is initially uncharged in the following situations.

(a) Just after the switch is closed
(b) After a long time when switch was closed.

Explanation

For just after closing the switch :
Potential difference across capacitor =0
` therefore " " Q_c= 0 therefore i= ( 10 )/( 2) =5A `
` (##MOT_CON_JEE_PHY_C25_SLV_035_S01.png" width="80%">
(b) After a long time
At steady state current i=0
and potential diffeence across capacitor =10 V
` (##MOT_CON_JEE_PHY_C25_SLV_035_S02.png" width="80%">
` therefore Q_c =3xx 10= 30 C `