Find the capacitance between A and B if three dielectric slabs of dielectric constants `K_(1) area `A _(2)` and thickness `d_(2)`) are inserted between the plates of a parallel late capacitor of plate area A. (Given that the distance between the two plates is `d_(1)=d_(2)+d_(2)`.)
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Explanation

It is equivalent to
` C= C_1 +( C_2C_5)/( C_2+ C_3) `
` C= ( A_1K_1in _0)/( d_1+d_2) +( (A_2K_2in _0)/(d_1) .(A_2K_3in _0)/(d_2)/(A_2K_2in _0)/(d_1)+(A_2K_3in_0)/( d_2)`
` =(A_1K_1in_0)/( d_1+d_2) +(A_2^(2) K_2K_5in _0^(2) )/( A_2K_2in_0d_2+ A_2K_5in _0 d_1 )`
` = (A_1K_1in_0)/( d_1+d_2) +(A_2K_2K_3in _0)/( K_2d_2+ K_3+d_1) `
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