A dielectric of constant K is slipped between the plates of parallel plate condenser in half of the space as shown in the figure. If the capacity of air condenser is C, then new capacitance between A and B will be
` (c )/(2) `
(B) ` (c )/(2K) `
(C) ` (C)/(2) [1+ K]`
(D) ` (2[1+ K])/(c ) `

Explanation

This system is equivalent to two capacitors in parallel with area of each plate ` (A)/(2) `
` C= C_1 +C_2`
` =(in _0A)/(2d) +(in _0 AK)/( 2d) `
` = (in _0A)/(2d) [1+K] =(c )/(2) [1+K]`
Hence the correct answer will be (c )