A parallel plate capacitor consists of two metal plates of area `A` and separation `d`. A slab of thickness `t` and electric constant `K` is inserted between the plates with its faces parallel to the plates and having the same surface area as that of the plates. Find the capacitance of the system.
IF `K=2`, for what value of `t//d` will the capacitance of the system be `3//2` times that of the air capacitor? Calculate the energy in the two cases and account for the energy change.

Options

A. ` (1)/(3) `
B. ` ( 2)/(3) `
C. ` ( 3)/(2) `
D. ` 3`

Answer

B