Two identical capacitors `1` and `2` are connected in series to a batery as shown in figure. Capacitor `2` contains a dielectric slab of dieletric constant `k` as shown. `Q_(1)` and `Q_(2)` are the charges stored in the capacitors. Now the dielectirc slab us removed and the corresponding charges are `Q'_(1)` and `Q'_(2)`. Then

Options

A. ` ( Q'_1)/(Q_1) =(K+1)/(K) `
B. ` (Q'_2)/(Q'_2) =(K+1)/(2) `
C. ` (Q'_2)/(Q'_2) =(K+1)/(2K)`
D. ` (Q'_1)/(Q'_1)=(K)/(2) `

Answer

C