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Let K(1) be the maximum kinetic energy o...

Let `K_(1)` be the maximum kinetic energy of photoelectrons emitted by a light of wavelength `lambda_(1)` and `K_(2)` corresponding to `lambda_(`2). If `lambda_(1) = 2lambda_(2)`, then

A

`2K_(1) = K_(2)`

B

`K_(1)=2K_(2)`

C

`K_(1) lt ( K_(2))/( 2)`

D

`K_(1) gt 2K_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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