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Electrons with de-Broglie wavelength lam...

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A

`lambda_(0) = ( 2 m c lambda^(2))/( h ) `

B

` lambda_(0) = ( 2h )/( mc ) `

C

` lambda_(0) = ( 2 m^(2) c^(2) lambda)/( h^(2))`

D

` lambda_(0) = lambda `

Text Solution

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The correct Answer is:
A
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