Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Explanation

Force exerted by one particle on another is
`F=("Gm"_(1)m_(2))/(r^(2))=(6.67xx10^(-11)xx1xx2)/((0.5)^(2))`
`=5.34xx10^(-10)N`
Acceleration of heavier particle =
`(F)/(m_(2))=(5.3xx10^(-10))/(2)=2.67xx10^(-10)ms^(-2)`
Note: This example shows that gravitational is quite weak but this is the only force keep binds our solar system and also the universe comprising of all galaxies and other interstellar system.