Find free electrons per unit volume in a wire of density `10^(4)kg//m^(3)`, atomic mass number 100 and number of free electron per atom is one.

Explanation

Number of free charge particle per unit volume
`(n)=("total free charge particle")/("total volume")`
`:.` Number of free electron per atom means total free electrons = total number of atoms.
`=N_A/M_WxxM`
So `n=(N_A/M_WxxM)/V=N_A/M_Wxxd`
`=(6.053xx10^23xx10^4)/(100xx10^-3)`
`n=6.023xx10^28 m^-3`