The dimensions of a conductor of specific resistance p are shown. Find the resistance of the conductor across AB, CD and EF.

Answer

`R_(AB)=(rhoc)/(ab), R_(CD)=(rhob)/(ac), R_(EF)=(rhoa)/(bc)`

Explanation

For a condition
`R=(rhot)/A=("Restivity" xx "length")/("Area of cross section")` `R_(AB)=(rhoc)/(ab), R_(CD)=(rhob)/(ac), R_(EF)=(rhoa)/(bc)`