The wire is strectched to increase the length by 1%. Find the percentage change in the resistance.

Explanation

As we known that
`:.R=(rhol)/A`
`(/_\R)/R=(/_\rho)/rho+(/_\l)/l-(/_\A)/A and (/_\l)/l=-(/_\A)/A`
`(/_\R)/R=O+1+1=2`
Hence percentage increase in the Resistance = 2%