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A conducting wire has resistance of 10 O...

A conducting wire has resistance of `10 Omega` at `0^@C` and `alpha` is `(1/273)^@C^(-1)`, then determine its resistance at `273^@C`

Text Solution

Verified by Experts

In such a problem, term `alpha delta`
T will have a larger value so could not be used directly in
`R=R_0(1+alpha/_\T)`. We need to go for basics as
As we know that `alpha=(dR)/(RdT)`
`rArrint(dr)/R=intalphadT`
`rArrl nR_2/R_1=alpha(T_2-T_1)`
`rArrR_2=R_1e^(alpha(T_2-T_1))`
`rArrR_2=10e^1`
`R_2=10eOmega`
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