Find the current in each wire applying only Kirchhoff voltage law

Explanation

Applying kirchoff voltage law in loop ABEFA
`i_1+30+2(i_1+i_2)-10=0`
`3i_1+2i_2+20=0` ...... (i)
Applying kirchoff voltage law in BEDCB
`+30+02+2(i_1+i_2)+50+2i_2=0`
`4i_2+2i_1+80=1`
`2i_2+i_1+40=0` ..........(ii)
Solving (i) and (ii)
`3[-40-2i_2]+2i_2+20=0`
`-120-4i_2+20=0`
`i_2=25 A`
and `i_1=10` A
`:.` `i_1+i_2=-15 A`
current in wire AF = 10 A from A to F
current in wire EB = 15 A from B to E
current in wire DE = 25 A from E to D.