Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width `12xx10^(-5)cm` when the slit is illuminated by monochromatic light of wavelength 6000 Å.

Explanation

`becausesintheta=lamda/a`
`theta`= half angular width of the central maximum.
`a=12 times10^-5 cm, lamda=6000 dotA=6 times10^-5 cm`
`therefore sintheta=lamda/a=(6 times10^-5)/(12 times10^-5)=0.50`
`implies theta=30^@`