While using a microscope it is found that the semivertical angle is `15^@`. Calculate the limit of resolution and resolving power when light of wavelength 540 nm illuminates the specimen.

Explanation

`Given theta=15^@, lamda=540 mm`for air n=1
Limit of resolution of the microscope for non-luminous object is
`dx=(1.22 lamda)/(2n sin theta)=(1.22 times540 times10^-9)/(2 times1 times sin15^@)`
`=(1.22 times540 times10^-9)/(2 times1 times 0.2588)=1.27 times10^-8m`
Resolving power `=1/(dx)=1/(1.27 times10^-6)`
`=7.87 times10^5`