In White light interference, nearest to the central (bright) fringe, will have which of the following colour

Options

A. violet
B. yellow
C. red
D. green

Answer

To solve the question regarding the color nearest to the central bright fringe in white light interference, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding White Light Interference**:
In Young's double-slit experiment, when white light is used instead of monochromatic light, we observe multiple colors due to the different wavelengths of light present in white light.

**Hint**: Remember that white light consists of a spectrum of colors, each with different wavelengths.

2. **Identifying the Central Bright Fringe**:
The central bright fringe (central maxima) is formed due to constructive interference of light waves. This fringe is where all wavelengths overlap, resulting in white light.

**Hint**: The central fringe is always white because it combines all colors.

3. **Understanding Fringe Width**:
The fringe width (β) is given by the formula:
\[ \beta = \frac{2\lambda D}{d} \]
where \( \lambda \) is the wavelength of light, \( D \) is the distance from the slits to the screen, and \( d \) is the distance between the slits.

**Hint**: The fringe width is directly proportional to the wavelength; longer wavelengths produce wider fringes.

4. **Determining the Color Nearest to the Central Fringe**:
The nearest fringe to the central maximum will correspond to the shortest wavelength of light in the spectrum of white light. In the visible spectrum, violet has the shortest wavelength, while red has the longest.

**Hint**: Recall the order of colors in the visible spectrum: Red, Orange, Yellow, Green, Blue, Indigo, Violet (ROYGBIV).

5. **Conclusion**:
Since violet light has the shortest wavelength, it will be the color nearest to the central bright fringe in white light interference.

**Final Answer**: The color nearest to the central bright fringe is **violet**.