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Two coherent sources of equal intensitie...

Two coherent sources of equal intensities produce a maximum of 100 units. If the amplitude of one of the sources is reduced by 20%, then the maximum intensity produced will be :

A

100

B

81

C

89

D

60

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's follow the reasoning outlined in the video transcript. ### Step 1: Understand the Initial Conditions We have two coherent sources of equal intensity, denoted as \( I_0 \). The maximum intensity produced by these two sources is given as 100 units. ### Step 2: Determine the Initial Intensity Since the maximum intensity \( I_{\text{max}} \) for two coherent sources of equal intensity is given by the formula: \[ I_{\text{max}} = 4I_0 \] We can set up the equation: \[ 4I_0 = 100 \] From this, we can solve for \( I_0 \): \[ I_0 = \frac{100}{4} = 25 \text{ units} \] ### Step 3: Adjust the Amplitude of One Source Now, we reduce the amplitude of one of the sources by 20%. If the original amplitude of the source is \( A \), the new amplitude becomes: \[ A' = 0.8A \] ### Step 4: Relate Amplitude to Intensity Intensity is proportional to the square of the amplitude. Therefore, if the intensity of the first source is \( I_0 \) (which corresponds to amplitude \( A \)), the new intensity \( I' \) of the modified source becomes: \[ I' = k(0.8A)^2 = k(0.64A^2) = 0.64I_0 \] where \( k \) is a constant of proportionality. ### Step 5: Calculate the New Intensity Substituting \( I_0 = 25 \) units into the equation for \( I' \): \[ I' = 0.64 \times 25 = 16 \text{ units} \] ### Step 6: Find the New Maximum Intensity Now we have two intensities: one is \( I_0 = 25 \) units and the other is \( I' = 16 \) units. The new maximum intensity \( I_{\text{max}}' \) can be calculated using the formula: \[ I_{\text{max}}' = \left( \sqrt{I_0} + \sqrt{I'} \right)^2 \] Calculating the square roots: \[ \sqrt{I_0} = \sqrt{25} = 5 \] \[ \sqrt{I'} = \sqrt{16} = 4 \] Now substituting back into the formula: \[ I_{\text{max}}' = (5 + 4)^2 = 9^2 = 81 \text{ units} \] ### Final Answer The maximum intensity produced after reducing the amplitude of one source by 20% is: \[ \boxed{81 \text{ units}} \]
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