If `(x^4+2)/((x-1)^2(x+1))=(x+1)+A/(x-1)+3/(2(x-1)^2)+B/(x+1)` then the equation of line passing through point `(0,2)` with the slope `B/A` is

Derive the equation of the line passing through two points ( x_ 1,y_1) and ( x_2,y_2)

Equation of the plane passing through the points A(2,1,-1), B(3,1,2) and parallel to X-axis, is

If the slope of a line passing through the points (1,4) and (x,2) is 2 , find the value of x .

If the slope of a line passing through the points (1,4) and (x,2) is 2 , find the value of x .

Slope of the line passing through the points (1,5) and(x,6) is 1 //2 . Find the value of x.

If m_(1),m_(2) are slopes of lines represented by 2x^(2)-5xy+3y^(2)=0 then equation of lines passing through origin with slopes 1/(m_(1)),1/(m_(2)) will be

If m_(1),m_(2) are slopes of lines represented by 2x^(2)-5xy+3y^(2)=0 then equation of lines passing through origin with slopes 1/(m_(1)),1/(m_(2)) will be

A : The equation of the line passing through (1, 2) with slope 2//5 is 2x-5y+8=0 R : The equation of the line passing through (x_(1), y_(1)) with slope m is y-y_(1)=m(x-x_(1))

(i) Find the equations of the straight line passing through the point (2,3,-1) and is perpendicular to the lines : ( x-2)/(2) = (y + 1)/(1) = (z - 3)/(-3) and (x - 3)/(1) = (y + 2)/(1) = (z - 1)/(1) . (ii) Find the equation of the line which intersects the lines : (x + 2)/(1) = (y - 3)/(2) = (z + 1)/(4) and (x - 1)/(2) = (y - 2)/(3) = (z - 3)/(4) Perpendicular and passes through the point (1,1,1) .