The intensity at the maximum in a Young's double slit experiment is `I_(0^.)` Distance between two slits is `d=5 lamda,` where `lamda` is the wavelength of light used in the experment. What will be that intensity in front of one of the slit on the screen placed at a distance at a distance D=10 d ?

Options

A. `I_0`
B. `I_0/4`
C. `3/4 I_0`
D. `I_0/2`

Answer

D